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Let equations of line PQ, PR and QR are 2x - y -2 = 0, 4x + 3y = 24 and y + 4 = 0 respectively then find the length of perpendicular drawn from vertex P on QROptions3486​

Answer»

equations of line PQ, PR and QR are 2x - y -2 = 0, 4x + 3Y = 24 and y + 4 = 0 respectively To Find : the length of perpendicular drawn from VERTEX P  on QRSolution: PQ  2x - y -2 = 0  => 4x - 2y  - 4  = 0 PR   4x + 3y = 24 P is INTERSECTION of PQ & PR =>  5y + 4 = 24 => 5y = 20 => y = 4  2x - y -2 = 0 => 2x - 4 - 2 = 0=> x = 4P = (3 , 4) y + 4 = 0   is  QRy = - 4 Vertex P = ( 3 , 4) length of perpendicular drawn from vertex P   on QR  ( 3, - 4) = 4 -(-4)= 8 8 is  the length of perpendicular drawn from vertex P  on QRLearn More:The length of the perpendicular drawn from the point (4, - 7, 3) on ... brainly.in/question/16066837the area of a quadrilateral is 360 m square and the perpendicular ... brainly.in/question/2561718



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