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Let `f:A->B` be a function defined by `f(x) sqrt3sin x +cos x+4.` If `f` is invertible, thenA. `A=[-2pi//3, pi//3], B=[2,6]`B. `A=[pi//6, 5pi//6], B=[-2,2]`C. `A=[-pi//2, pi//2], B=[2,6]`D. `A=[-pi//3, pi//3], B=[2,6]`

Answer» Correct Answer - A


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