1.

Let`f:[-oo,0]->[1,oo)` be defined as `f(x) = (1+sqrt(-x))-(sqrt(-x) -x)`, thenA. injective but not surjectiveB. injective as well as surjectiveC. neither injective nor surjectiveD. surjective but injective

Answer» Correct Answer - B
`f(x)=(1+sqrt(-x))-(-sqrt(-x)-x)`
`=1-x, x le0`
Then `1-x ge 1`.
Hence function is injective and surjective.


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