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Let`f:[-oo,0]->[1,oo)` be defined as `f(x) = (1+sqrt(-x))-(sqrt(-x) -x)`, thenA. injective but not surjectiveB. injective as well as surjectiveC. neither injective nor surjectiveD. surjective but injective |
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Answer» Correct Answer - B `f(x)=(1+sqrt(-x))-(-sqrt(-x)-x)` `=1-x, x le0` Then `1-x ge 1`. Hence function is injective and surjective. |
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