InterviewSolution
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Let f : R → R be defined as f (x) = x2 + 1. Then find f –1(– 5)(a) {0} (b) ϕ (c) {5} (d) {– 5, 5} |
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Answer» Answer: (b) = ϕ f (x) = x2 + 1 Let y = f (x) = x2 + 1 ⇒ y – 1 = x2 ⇒ x = ± \(\sqrt{y-1}\) ⇒ f –1(x) = ± \(\sqrt{x-1}\) ∴ f –1(– 5) = ± \(\sqrt{-5-1}\) ± \(\sqrt{-6}\) ∉ R ∴ f –1(– 5) is the null set. |
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