1.

Let f : R+ → R : f(x) = loge x. Find {x : f(x) = –2}.

Answer»

Given, f : R+ → R : f(x) = loge

f(x) = -2 

loge x = -2 

Taking antilog on both sides 

x = e-2

Hence, the value of x for which f(x) = -2 is e-2



Discussion

No Comment Found