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Let f : R → R : f(x) = x2 + 1. Find f–1 {10}. |
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Answer» Given: f : R → R : f(x) = x2 + 1 To find inverse of f(x) Let y = f(x) y = x2 + 1 y -1 = x2 x = \(\sqrt{y-1}\) f-1 (x) = \(\sqrt{x-1}\) Substituting x = 10 f–1 (10) = \(\sqrt{10-1}\) = √9 = 3 |
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