1.

Let f : R → R : f(x) = x2 + 1. Find f–1 {10}.

Answer»

Given: 

f : R → R : f(x) = x2 + 1 

To find inverse of f(x) 

Let y = f(x) 

y = x2 + 1 

y -1 = x2

x = \(\sqrt{y-1}\)

f-1 (x) = \(\sqrt{x-1}\)

Substituting x = 10

f–1 (10) = \(\sqrt{10-1}\) = √9 = 3



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