1.

Let `f : R to R` be a function such that `f(0)=1` and for any `x,y in R, f(xy+1)=f(x)f(y)-f(y)-x+2.` Then `f` isA. one-one and ontoB. one-one but not ontoC. many one but ontoD. many one and into

Answer» Correct Answer - A
`f(xy+1)=f(yx+1)`
`f(x)f(y)-f(y)-x+2=f(y)f(x)-f(x)-y+2`
`f(x) -f(y)=x-y`
Putting `y=0`
`f(x)-1=x-0`
`f(x) = x+1`


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