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Let F(x) be an indefinite integral of `sin^(2)x` Statement I The function F(x) satisfies `F(x+pi)=F(x)` for all real x. Because Statement II `sin^(2)(x+pi)=sin^(2)x,` for all real x.(A) Statement I is true, Statement II is also true, Statement II is the correct explanation of Statement I.(B)Statement I is true, Statement II is also true, Statement II is not the correct explanation of Statement I.(C) Statement I is true, Statement II is false.(D) Statement I is false, Statement II is ture.A. Statement I is true, Statement II is also true, Statement II is the correct explanation of Statement I.B. Statement I is true, Statement II is also true, Statement II is not the correct explanation of Statement I.C. Statement I is true, Statement II is false.D. Statement I is false, Statement II is ture. |
Answer» Correct Answer - D Given, `F(x)=int sin^(2)x dx= int(1-cos2x)/(2)dx` `F(x)=(1)/(4)(2x-sin 2x)+C` Since, `F(x+pi) ne F(x)` Hence, Statement I is false. But, Statement II is true as `sin^(2)x` is periodic with period `pi`. |
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