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Let f (x) = (x + 2)2 – 2, x ≥ – 2, then f -1(x) is equal to(a) \(- \sqrt{2+x}\) - 2(b) \( \sqrt{2+x} +2\)(c) \( \sqrt{2+x} -2\)(d) \(- \sqrt{2+x}+2\) |
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Answer» Answer : (c) \( \sqrt{2+x}-2\) Let y = f (x) = (x + 2)2 – 2 ⇒ y + 2 = (x + 2)2 ⇒ x + 2 = \(\sqrt{y+2}\) ⇒ x = \(\sqrt{y+2}\) - 2 ⇒ f-1 (x) = \( \sqrt{2+x}-2\) |
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