Let `f(x)=x^2`and `g(x)=2^x`. Then the solution setof the equation `fo – InterviewSolution

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1.	Let `f(x)=x^2`and `g(x)=2^x`. Then the solution setof the equation `fog(x)=gof(x)`is`R`(b) {0} (c) {0, 2} (d) none of theseA. RB. {0}C. {0,2}D. None of these
Answer» Correct Answer - C We have `f(x)=x^(2) and g(x)=2^(x)` `therefore fog(x)=g of (x)` `Rightarrow f(g(x))=g(f(x))` `Rightarrow f(2^(x))=g(x^(2))` `Rightarrow (2^(x))^(2)=2^(x^(2))` `Rightarrow 2^(2x)=2^(x^(2))Rightarrow 2x=x^(2) Rightarrow x(2-x)=0Rightarrow x=0,2`

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