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Let `g(x)=1+x-[x] and f(x)={(-1",",x lt 0),(0",",x=0),(1",",x gt 0):}`, then for all `x, f[g(x)]` is equal toA. xB. 1C. f(x)D. g(x) |
Answer» Correct Answer - B `g(x)=1+x-[x]` is grater than 1 since `x[x] gt 0` `f[g(x)]," since " f(x) =1 " for all " x gt 0` |
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