1.

Let g(x) be a function defined on [-1, 1]. If the area of the equilateral trianglewith two of its vertices at (0, 0) and (x, g(x)) is sqrt(3)//4, then the function g(x) is

Answer»

`g(X)= pm sqrt(1-x^(2))`
`g(x)=sqrt(1-x^(2))`
`g(x)= - sqrt(1-x^(2))`
`g(x)= sqrt(1+x^(2))`

Answer :B::C


Discussion

No Comment Found