Let g(x) be a function defined on [-1,1]. If the area of the equilater – InterviewSolution

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1.	Let g(x) be a function defined on [-1,1]. If the area of the equilateral triangle with two of its vertices at `(0,0)` and `(x,g(x))` is `sqrt(3)/4`.then the function g(x) is:
Answer» side length(a)=`sqrt((x-0)^2+(g(x)-0)^2` `a=sqrt(x^2+g(x)^2` Area of equilateral triangle=`sqrt3/4a^2` `sqrt3/4a^2=sqrt3/4` `a^2=1` `x^2+g(x)=1` `g(x)^2=1-x^2` `g(x)=pmsqrt(1-x^2`.

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