1.

Let hydrolysis constant (K_(h)) ofoverset(+)NH_(4) be y. Then equilibrium constant (K_(a)) for conjugate acid of NH_(3) at 25^(@)C is :

Answer»

`(1)/(y)xx10^(-14)`
`10^(-14)`
`y`
`yxx10^(-14)`

Solution :`NH_(4)^(+)+H_(2)OhArr NH_(4)OH+H^(+):K_("EQ")=K_(h)=K_(a(NH_(4)^(+)))`


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