1.

Let m_p be the mass of a proton , m_n the mass of a neutron, M_1 the mass of a ._10^20Ne nucleus and M_2 the mass of a ._20^40Ca nucleus . Then

Answer»

`M_2 = M_1`
`M_2 GT M_1`
`M_2 lt 2M_1`
`M_1 lt 10 (m_n + m_p)`

Solution :Due to MASS defect, the rest mass of a nucleus is always less than sum of the rest masses of its CONSTITUENT nucleons.
`._10^20Ne` nucleus CONSISTS of 10 protons and 10 neutrons .
`therefore M_1 lt 10 (m_p + m_n)`


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