Let ` n=10lambda+r", where " lambda,rinN, 0lerle9.` A number a is chosen at random from the set {1, 2, 3,…, n} and let `p_n` denote the probability that `(a^2-1)` is divisible by 10. If r=0, then `np_n` equalsA. `2lambda`B. `(lambda+1)`C. `(2lambda+1)`D. `lambda`

Let ` n=10lambda+r", where " lambda,rinN, 0lerle9.` A number a is chos

1.	Let ` n=10lambda+r", where " lambda,rinN, 0lerle9.` A number a is chosen at random from the set {1, 2, 3,…, n} and let `p_n` denote the probability that `(a^2-1)` is divisible by 10. If r=0, then `np_n` equalsA. `2lambda`B. `(lambda+1)`C. `(2lambda+1)`D. `lambda`
Answer» Correct Answer - (a)

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Let ` n=10lambda+r", where " lambda,rinN, 0lerle9.` A number a is chosen at random from the set {1, 2, 3,…, n} and let `p_n` denote the probability that `(a^2-1)` is divisible by 10. If r=0, then `np_n` equalsA. `2lambda`B. `(lambda+1)`C. `(2lambda+1)`D. `lambda`

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