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Let n(U)=700,n(A)=200,n(B)=300 and n(AnB)=100 then what is n(A'nB')? |
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Answer» Answer: Correct option is C =n(U)−n(A∪B) =n(u)−{n(A)+n(B)−n(A∩B)} =700−{200+300−100}=300 |
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