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Let `P=0`be the equation of a plane passing through the line ofintersection of the planes `2x-y=0a n d3z-y=0`and perpendicular to the plane `4x+5y-3z=8.`Then the points which lie on the plane `P=0`is/area. `(0,9,17)`b. `(1//7,21//9)`c. `(1,3,-4)`d. `(1//2,1,1//3)`A. (0,9,17)B. `(1//7,2,1//9)`C. (1,3,-4)D. `(1//2,1,1//3)` |
Answer» Correct Answer - a, d The equation of the plane through the intersection of the planes `2x-y=0 and 3z-y=0` is `" "2x-y+lamda(3z-y)=0" "`(i) or `" "2x-y(lamda+1)+3ladmaz=0` Plane (i) is perpendicular to `4x+5y-3z=8`. Therefore, `" "4xx2-5(lamda+1)-9lamda=0` or `" "8-5lamda-5-9lamda=0` or `" "3-14lamda=0` or `" "lamda= 3//4` `therefore" "2x-y+ (3)/(14) (3z-y)=0` `" "28x-17y+9z=0` |
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