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    				| 1. | Let `P=-(1,7,sqrt(2))` be a point and line L is `2sqrt(2)(x-1)=y-2,z=0`. If PQ is the distance of plane `sqrt(2)x+y-z=1` from point P measured along a line inclined at an angle of `45^(@)` with the line L and is minimum then the value of PQ isA. 3B. 4C. 6D. 8 | 
| Answer» Correct Answer - A Line L is `(x-1)/1=(y-2)/2sqrt(2)=z/0` This line L makes an angle of `45^(@)` with the plane `sqrt(2)x+y-z=1` `therefore` Required distance PQ is prependicular distance of plane from P I.e., `PQ=(|sqrt(2)+7-sqrt(2)-1|)/sqrt(2+1+1)=3` | |