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Let `P(x)=5/4+6x-9x^2a n dQ(y)=-4y^2+4y+(13)/2dot`if there exists unique pair of real numbers `(x , y)`such that `P(x)Q(y)=20`, then the value of `(6x+10 y)`is _____. |
Answer» Correct Answer - 3 We have `P(x)=(5)/(3)-6 x-9x^(2)=-(3x+1)^(2)=-(3x+1)^(2)+(8)/(3)` `impliesP_("max")=(8)/(3)` Similarly, `Q(y)=-4y^(2)+4y+(13)/(2)=-(2y-1)^(2)+(15)/(2)` `Q_(max)=(15)/(2)` Now, `P_(max)xxQ_("max)=(8)/(3)xx(15)/(2)=20` So, `(x,y)-=(-(1)/(3),(1)/(2))` Hence, `6x+10y=6((-1)/(3))+10((1)/(2))=-2+5=3` |
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