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Let PS be the median of the triangle with vertices P(2, 2),Q(6,-1) and (7,3). The equation of the line passing through (1.-1) and parallel to PS is:please answer me |
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Answer» 2x + 9y + 7 = 0Step-by-step explanation:Since S is mid point of Q and R∴S=( 27+6 , 23−1 )=( 213 ,1)Slope of PS=m= X 2 −x 1 y 2 −y 1 = 2− 213 2−1 = 9−2 Equation of the LINE PASSING through (1,−1) and parllel to PS is y−(−1)= 9−2 (x−1)y+1= 9−2x+2 ⇒9y+9+2x−2=0⇒2x+9y+7=0 |
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