1.

Let PS be the median of the triangle with vertices `P(2,""2),""Q(6,-1)""a n d""R(7,""3)`. The equation of the linepassing through `(1,-1)`and parallelto PS is(1) `4x-7y-11""=""0`(2) `2x+""9y+""7""=""0`(3) `4x+""7y+""3""=""0`(4) `2x-9y-11""=""0`A. 4x-7y-1=0B. 2x+9y+7=0C. 4x+7y+3=0D. 2x-9y-11=0

Answer» Correct Answer - B
S is the midpoint of QR,
`therefore S((13)/(2), 1)`
Slope of PS `=-(2)/(9)`
`therefore " Equation of required line is: " y+1 = -(2)/(9)(x-1)`
`therefore 2x+9y+7=0`


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