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Let PS be the median of the triangle with vertices `P(2,""2),""Q(6,-1)""a n d""R(7,""3)`. The equation of the linepassing through `(1,-1)`and parallelto PS is(1) `4x-7y-11""=""0`(2) `2x+""9y+""7""=""0`(3) `4x+""7y+""3""=""0`(4) `2x-9y-11""=""0`A. 4x-7y-1=0B. 2x+9y+7=0C. 4x+7y+3=0D. 2x-9y-11=0 |
Answer» Correct Answer - B S is the midpoint of QR, `therefore S((13)/(2), 1)` Slope of PS `=-(2)/(9)` `therefore " Equation of required line is: " y+1 = -(2)/(9)(x-1)` `therefore 2x+9y+7=0` |
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