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Let PS be the median of the triangle with vertices `P(2,""2),""Q(6,-1)""a n d""R(7,""3)`. The equation of the linepassing through `(1,-1)`and parallelto PS is(1) `4x-7y-11""=""0`(2) `2x+""9y+""7""=""0`(3) `4x+""7y+""3""=""0`(4) `2x-9y-11""=""0` |
Answer» slope of line `PS= (2-1)/(2- 13/2)` `= -2/9` slope of line `AB= m= -2/9` point `(1,-1)` `y- y_1 = m(x- x_1)` `y + 1 = - 2/9 (x-1)` `9y + 9 = -2x+2` `2x + 9y + 7=0` option 2 is correct |
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