1.

Let R = {(a, b): a = b2} for all a, b ∈ N.Show that R satisfies none of reflexivity, symmetry and transitivity.

Answer»

It is given that

R = {(a, b): a = b2} for all a, b ∈ N

Reflexivity-

By substituting 2 we get

2 ≠ 22 where 2 is not related to 2

It can be written as

(2, 2) ∉ R

Hence, R is not reflexive.

Symmetry-

By substituting 4 we get

4 = 22

It can be written as

(4, 2) ∈ R and (2, 4) ∉ R

Hence, R is not symmetric.

Transitive-

Here, we know that (16, 4) ∈ R and (16, 2) ∉ R

Therefore, R is not transitive.



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