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Let R = {(a, b): a = b2} for all a, b ∈ N.Show that R satisfies none of reflexivity, symmetry and transitivity. |
Answer» It is given that R = {(a, b): a = b2} for all a, b ∈ N Reflexivity- By substituting 2 we get 2 ≠ 22 where 2 is not related to 2 It can be written as (2, 2) ∉ R Hence, R is not reflexive. Symmetry- By substituting 4 we get 4 = 22 It can be written as (4, 2) ∈ R and (2, 4) ∉ R Hence, R is not symmetric. Transitive- Here, we know that (16, 4) ∈ R and (16, 2) ∉ R Therefore, R is not transitive. |
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