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Let the angles `A , Ba n dC`of triangle `A B C`be in `AdotPdot`and let `b : c`be `sqrt(3):sqrt(2)`. Find angle `Adot` |
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Answer» Correct Answer - `(5pi)/(12)` Angles are in A.P., so, `B = (pi)/(3)` Also, `(b)/(c) = (sqrt3)/(sqrt2) " or " (b)/(sqrt3) = (c)/(sqrt2) " or " (b)/((sqrt3)/(2)) = (c)/((1)/(sqrt2))` But we know that `(b)/(sin B) = (c)/(sin C) = (a)/(sin A)` `:. B = (pi)/(3), C = (pi)/(4) rArr A = (5pi)/(12)` |
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