1.

Let the X - Z plane be the boundary between two transparent media. Medium 1 in Z ge 0 hasrefractive index ofsqrt(2) and medium 2 with Z lt 0 has a refractive index of sqrt(3). A ray of light in medium 1 given by the vertor overset(rarr)(A)=6sqrt(3hat(i))+8sqrt(3)hat(j)-10hat(k) is incident on the plane of separation. The angle of refraction in medium 2 is :

Answer»

`45^(@)`
`60^(@)`
`75^(@)`
`30^(@)`

Solution :(a)
`cosi(A_(Z))/(|A|)=(-10)/((sqrt(6sqrt3))^(2)+(8sqrt(3))^(2)+(-10)^(2))=-(1)/(2)`
`therefore I = 60^(@) ("since I lies between" 0^(@) and 90^(@) "HENCE" 120^(@) "is not possible")`
By using Snell.s LAW,
`mu_(1) sin I = mu_(2) sin R`
`sqrt(2) sin 60^(@) = sqrt(3) sin r`
`rArr "" sin r = (1)/(sqrt(2)) rArr r = 45^(@)`


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