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Let two cell of e.m.f's E_1 and E_2 and internal resistances r_1 and r_2 be connected in parallel to a circuit with an external resistance R. Find the value of the current I through the given resistor .

Answer»

SOLUTION :ELECTRIC cells connected in parallel to an EXTERNAL resistor. The CURRENT through the given resistor

`I = ((E_1)/(r_1) + (E_2)/(r_2))/(1+ R[1/r_1 + 1/r_2]) = ((E_1 r_2 + E_2 r_1)/(r_1 r_2))/(1+ (R[r_1 +r_2])/(r_1 r_2))`
`I= (E_1 r_2 + E_2 r_1)/(r_1 r_2+ R[r_1 + r_2])`


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