InterviewSolution
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InterviewSolution
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Let us consider that our galaxy consists of `2.5xx10^(11)` stars each of one solar mass. How long will this star at a distance of `50,000` light year from the galastic entre take to complete one revolution? Take the diameter of the Milky way to be `10^5ly. G=6.67xx 10^(-11) Nm^(2) Kg^(-2). (1 ly= 9.46xx10^(15)m)` |
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Answer» Here `M=2.5xx10^(11)` solar mass `=2.5xx10^(11)xx(2xx10^(30))kg=5.0xx10^(41) kg` `1r=50,00ly=50,000xx9.46xx10^(15) m` `=4.73xx10^(20)m` We know that, `M=(4pi^(2)r^(3))/(GT^(2))` `T=((4pi^(2)r^(3))/(GM))^(1/2)=[(4xx(22//7)^(2)xx(4.73xx10^(20))^(3))/((6.67xx10^(-11))xx(5.0xx10^(41)))]^(1/2)` `=3.53xx10^(14)s` |
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