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Let us write the value of k for which 3 will bea root of the Quadratic equation 7x2 + KX-3=0 |
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Answer» Answer: 7x² + KX-3=0 So ATQ, 7(3)² + K(3) - 3 = 0 7 x 9 + 3k -3 = 0 63 - 3 + 3k = 0 60 = -3k 60/(-3) = k -20 = k Ans Hope this HELPS ☺️ |
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