1.

Let veca= 2 hati + 3hatj - 6hatk, vecb = 2hati - 3hatj + 6hatk and vecc = -2 hati + 3hatj + 6hatk. Let veca_(1) be the projection of veca on vecb and veca_(2) be the projection of veca_(1) on vecc . Thenveca_(1).vecb is equal to

Answer»

`-41`
`-41//7`
41
287

Solution :`veca_(1).VECB= (-41)/49 (2hati - 3hatj + 6hatk) . (2hati - 3hatj + 6hatk) =-41`


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