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Let `veca=2hati=hatj+hatk, vecb=hati+2hatj-hatk and vecc=hati+hatj-2hatk` be three vectors . A vector in the pland of `vecb and vecc` whose projection on `veca` is of magnitude `sqrt((2/3))`is (A) `2hati+3hatj+3hatk` (B) `2hati+3hatj-3hatk` (C) `-2hati-hatj+5hatk` (D) `2hati+hatj+5hatk`A. `2hati+3hatj-3hatk`B. `2hati+3hatj +3hatk`C. `-2hati - hatj + 5hatk`D. `2hati + hatj + 5hatk` |
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Answer» Correct Answer - a,c we have `veca =2hati-hatj+hatk,vecb=hati+2hatj-hatk,vecc=hati+hatj=2hatk` Any vector in the plane of `vecb and vecc` is `vecu=muvecb+lamdavecc` ` mu(hati+2hatj-hatk)+lamda(hati +hatj-2hatk)` `=(mu+lamda)hati+(2mu+lamda)hatj-(mu + 2lamda)hatk` Given that the magnitude of projection of `vecu "on " veca` is `sqrt(2//3)` thus `sqrt(2/3)=|(vecu.veca)/(|veca|)|` `|(2(mu+lamda)-(2mu+lamda) -(mu+2lamda))/sqrt6|` `or |-lamda- mu|2` ` Rightarrow lamda + mu=2 or lamda+mu =-2` |
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