InterviewSolution
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InterviewSolution
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If `veca=xhati + y hatj + zhatk, vecb= yhati + zhatj + xhatk and vecc= zhati + xhatj+ yhatk ,, " then " vecaxx (vecbxx vecc) `isA. parallel to ` ( y- z) hati + (z - x) hatj + (x -y) hatk`B. orthogonal to `hati + hatj + hatk`C. orthogonal to ` ( y+z) hati + ( z + x) hatj + ( x + y) hatk`D. orthogonal to `xhati + yhatj + zhatk` |
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Answer» Correct Answer - a,b,c,d `veca xx (vecbxxvecc0 = (veca .vecc) vecb- (veca .vecb)vecc` `= (yz+yx +zx) {(y-z)hati+(z-x)hatj +(x-y)hatk}` Clearly vector is parallel to `(y-z) hati + (z-x) hatj + (x-y) hatk` it is orthogonal to `hati+hatj +hatk as (y-z) (1) + (z-x) (1) + (x-y) (1) =0` it is orhtogonal to `( y+z) hati+ (z+x) hatj + (x +y) hatk` as (y-z) (y+z) + (z+x) + (x-y) (x+y) ` = y^(2) -z^(2) +z^(2)- x^(2) +x^(2) -y^(2) =0` Also it is orthogonal to `xhati + yhatj + zhatk` |
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