Let `veca =veci -veck, vecb = xveci+ vecj + (1-x)veck and vecc =y veci +xvecj + (1+x -y)veck`. Then `veca, vecb and vecc` are non-coplanar forA. some values of xB. some values of yC. no values of x and yD. for all values of x and y

Let `veca =veci -veck, vecb = xveci+ vecj + (1-x)veck and vecc =y veci

1.	Let `veca =veci -veck, vecb = xveci+ vecj + (1-x)veck and vecc =y veci +xvecj + (1+x -y)veck`. Then `veca, vecb and vecc` are non-coplanar forA. some values of xB. some values of yC. no values of x and yD. for all values of x and y
Answer» Correct Answer - D `veca =hati -hatk ` `" " vecb = xhati +hatj + (1-x)hatk` `" " vecc =yhati + xhatj+ (1+x-y)hatk` `" "=\|{:(1,,0,,-1),(x,,1,,1-x),(y,,x,,1+x-y):}\|` `" " = 1+x-y-x^(2)+y-x+x^(2)` `= 1`

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Let `veca =veci -veck, vecb = xveci+ vecj + (1-x)veck and vecc =y veci +xvecj + (1+x -y)veck`. Then `veca, vecb and vecc` are non-coplanar forA. some values of xB. some values of yC. no values of x and yD. for all values of x and y

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