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Let X is a continuous random variable with probability density function `f(x)={{:(x/6+k,0lexle3),(0," otherwise"):}` The value of k is equal toA. `1/(12)`B. `1/3`C. `1/4`D. `1/6` |
Answer» Correct Answer - A `oversetoounderset(-oo)intf(x)dx=1rArr0+overset3underset0int(x/6+k)dx+0=1` `rArr" "[x^2/(12)+kx]_0^3=1rArr3/4+3k=1` `rArr" "3k=1/4rArrk=1/(12)` |
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