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Let z be the set of all integers andA = {(a, b) : a2 + 3b2 = 28, a, b e Z}B = {(a, b): a > b, a, b e Z}, then n(AB) is equal to(1) 1(2) 6(3) 3(4) 8 |
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Answer» (2) 6 Step-by-step explanation: A={(a,B):a 2 +3b 2 =28,a,b∈Z} ={(5,1),(−5,−1),(5,−1),(−5,1),(4,2),(−4,−2),(4,−2),(−4,2),(1,3),(−1,−3),(1,−3),(−1,3)} and B={(a,b):a ∴A∩B={(1,3),(−1,3),(−4,−2),(−4,2),(−5,−1),(−5,1)} ∴ The NUMBER of elements in A∩B is 6. |
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