Let `Z in C` with Im (z) = 10 and it satisfies `=(2z-n)/(2z+n)=2i-1` For some natural number n. thenA. n=20 and Re (z) =-10B. n=40 and Re (z) =10C. n=40 and Re(z)D. n=20 and Re (z)=10

Let `Z in C` with Im (z) = 10 and it satisfies `=(2z-n)/(2z+n)=2i-1` F

1.	Let `Z in C` with Im (z) = 10 and it satisfies `=(2z-n)/(2z+n)=2i-1` For some natural number n. thenA. n=20 and Re (z) =-10B. n=40 and Re (z) =10C. n=40 and Re(z)D. n=20 and Re (z)=10
Answer» Correct Answer - C Let z=x+10 I, as Im(z) = 10 ( given ) Since z satisfies `(2z-n)/(2z +n)=2i -1 , n ne N` `therefore (2x+20 i-n)=(2i -1)(2x+20 I +n)` `rArr (2x-n)+20 i=(-2 -n- 40 )+(4x+2n- 20)i` On comparing real imaginary parts ,we get `2x-n= -2 x-n 40 and 20 = 4x+2n-20` `rArr 4x = -40 and 20 = 4x 2n = 40 ` `rArr x=-10 and - 40 +2n = 40 rArr n = 40` So , n = 40 and x= Re (z) = -10

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Let `Z in C` with Im (z) = 10 and it satisfies `=(2z-n)/(2z+n)=2i-1` For some natural number n. thenA. n=20 and Re (z) =-10B. n=40 and Re (z) =10C. n=40 and Re(z)D. n=20 and Re (z)=10

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