lf the fundamental period of function `f(x)=sinx + cos(sqrt(4-a^2))x` – InterviewSolution

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1.	lf the fundamental period of function `f(x)=sinx + cos(sqrt(4-a^2))x` is `4pi`, then the value of a is/areA. `(sqrt(15))/(2)`B. `-(sqrt(15))/(2)`C. `(sqrt(7))/(2)`D. `-(sqrt(7))/(2)`
Answer» Correct Answer - A::B::C::D Period of `sinx " is " 2pi` and period of `cos (sqrt(4-a^(2))x) " is " (2pi)/(sqrt(4-a^(2))).` `implies LCM (2pi,(2pi)/(sqrt(4-a^(2))))=4pi` (given) i.e., `sqrt(4-a^(2))=(p)/(2) " where " p=1,3.` Hence ` a^(2) =(15)/(4),(7)/(4),a=+-(sqrt(15))/(2),+-(sqrt(17))/(2)`

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