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Light described at a place by the equation epsilon = (100 V/m)[sin(5 xx 10^(15)s^(-1))t + sin (8 xx 10^(15)s^(-1))t] falls on a metal surface having work function 2eV. Calculate the maximum kinetic energy of the photo electrons. |
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Answer» 5.27 EV `v= omega/(2PI) = (8 xx 10^(15))/(2pi)s^(-1)` `K.E._("max") = hv - phi` `K.E_("max") =(6.6 xx 10^(-34) xx 8 xx 10^(15))/(1.6 xx 10^(-19) xx 2 xx 3.14)-2` `=5.27 -2 = 3.27 eV` |
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