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Light from a source emitting two wavelengths lambda_(1) and lambda_(2) is made tyo fall on Young's double slit appratus after filtering one of the wavelengths.The position of interference pattern is noted.When filter is removed, both the wavelength are incident.It is found that maximum intentsity is produced where the fourth maxima occured intially. If the other wvaelength is filtered, at the same location, the third maxima is found. What is the ratio of wavelengths? |
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Answer» `4/3` For first wavelengths `(x_(4)) lambda_(1)= (4lambda_(1)D)/(d)` This must be EQUAL to `(x_(3))lambda_(2) = (3lambda_(2)D)/(d)` SINCE ` (x_(4))lambda_(1) = (x_(3))lambda_(2)` `therefore (4lambda_(1)D)/(d) = (3 lambda_(2)D)/(d)` `therefore (lambda_(1))/(lambda_(2)) = 3/4` |
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