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Light green (compound 'A')overset(Delta)(to)"white Residue(B)"overset("high")underset("Temp.")C+D+E (i)'D' and 'E' are two acidic gas. (ii) 'D' is passed through HgCl_(2) solution to give yellow ppt. (iii) 'E' is passed through water first and then H_(2)S is passed, white turbidity is obtained. (iv) A is water soluble and addition of HgCl_(2) in it, yellow ppt. is obtained but white ppt does not turn into grey on addition of excess solution of 'A' Q. 'C' is soluble in : |
| Answer» Answer :D | |