Light of described at a place by the equation E=(100)[sin5xx10^(15)]t+sin(8xx10^(15))t] falls on a metal surface having work function 2.0 eV. Calculate the maximum kinetic energy of the photoelectrons.

Light of described at a place by the equation E=(100)[sin5xx10^(15)]t+

1.	Light of described at a place by the equation E=(100)[sin5xx10^(15)]t+sin(8xx10^(15))t] falls on a metal surface having work function 2.0 eV. Calculate the maximum kinetic energy of the photoelectrons.
Answer» Solution :The light contains TWO DIFFERENT frequencies. The one with large frequency will cause photoelectrons with largest kinetic energy. This larger frequency is `v=(omega)/(2pi)=(8xx10^(16))/(2pi)Hz` The MAXIMUM kinetic energy of the photoelectrons is `K_(MAX)=hv-W` `=(4.14xx10^(-15)eVs)xx((8xx10^(15))/(2pi)s^(-1))-2.0eV` `=5.27eV-2.0eV=3.27eV`

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Light of described at a place by the equation E=(100)[sin5xx10^(15)]t+sin(8xx10^(15))t] falls on a metal surface having work function 2.0 eV. Calculate the maximum kinetic energy of the photoelectrons.

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