Saved Bookmarks
| 1. |
Light of frequency 8.41xx10^(14)Hz is incident on a metal surface. Electrons with their maximum speed of 7.5xx10^(5)ms^(-1) are ejected from the surface. Calculate the threshold frequency for photoemission of electrons. Also find the work function of the metal in electron volt (eV). Given Plank's constant h=6.625xx10^(-34)Js and mass of the electron 9.1xx10^(-31)kg. |
|
Answer» Solution :`K_(max)=hv-omega_0` `hv=hv_0+1/2 mv^2` `hv_0=(6.625xx10^(-34)xx8.41xx10^14)-1/2xx9.1xx10^(-31)xx(7.5xx10^5)^2` Calculation of threhold FREQUENTLY `v_0=4.54xx10^14` HZ Work FUNCTION , `omega_0=hv_0` Work function , `omega_0=(6.625xx10^(-34)xx4.54xx10^14)/(1.6xx10^(-19))` Work function , `omega_0`=1.88 eV |
|