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Light of frequency vis incident on a photosensitive surface of threshold frequency v_(0)(v gt v_(0)). The value of kinetic energy of the emitted photoelectrons will be ______ |
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Answer» Solution :`H(v-v_(0))` or less [Hint : Maximum kinetic ENERGY of the emitted photoelectrons `k_("max")=h(v-v_(0))`] |
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