1.

Light of frequency vis incident on a photosensitive surface of threshold frequency v_(0)(v gt v_(0)). The value of kinetic energy of the emitted photoelectrons will be ______

Answer»

Solution :`H(v-v_(0))` or less
[Hint : Maximum kinetic ENERGY of the emitted photoelectrons `k_("max")=h(v-v_(0))`]


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