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Light of two different frequencies whose photons have energies 1 eV and 2.5 eV respectively, successively illuminate a metallic surface whose work function is 0.5 eV. Ratio of maximum speeds of emitted electrons will be |
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Answer» `1: 1` `K_(1)= 1-0.5= 0.5eV` `K_(2)= 2.5- 0.5 = 2eV` `((1)/(2) mV_(1)^(2))/((1)/(2) mV_(2)^(2))= (0.5)/(2) RARR (V_(1)^(2))/(V_(2)^(2)) = (1)/(4) rArr (V_(1))/(V_(2))= (1)/(2)` |
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