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InterviewSolution
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Light of two different frequencies whose photons have energies 1 eV and 2.5 eV respectively, successively illuminate a metallic surface whose work function is 0.5 eV. Ratio of maximum speeds of emitted electrons will be: |
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Answer» SOLUTION :`hv=w+1//2mv_("max")^(2)` `i.e. E=w+1//2v_("max")^(2)` `:.1//2mv_("max")^(2)=E-w` `:.(v_(1)^(2))/(v_(2)^(2))=(E_(1)-w)/(E_(2)-w)` `(1eV-0.5eV)/(2.5eV-0.5eV)` `=(0.5)/(2)=(1)/(4)` `:.(v_(1))/(v_(2))=1//2` |
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