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InterviewSolution
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Light of wavelength `1824 Å`, incident on the surface of a metal , produces photo - electrons with maximum energy `5.3 eV`. When light of wavelength `1216 Å` is used , maximum energy of photoelectrons is `8.7 eV`. The work function of the metal surface isA. `3.5 eV`B. `13.6 eV`C. `6.8 eV`D. `1.5 eV` |
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Answer» Correct Answer - D `E = W_(0) + K_(max)`. "From the given data" `E is 6.78 eV` ( for `lambda = 1824 Å)` or `10.17 ev ( for lambda = 1216 Å)` `:. W_(0) = E - K_(max) = 6.78 - 5.3 = 1.48 eV` or `W_(0) = 10.17 - 8.7 = 1.47 eV`. |
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