1.

Light of wavelength 2000 Å falls on a metallic surface whose work function is 4.21 eV. Calculate the stopping potential

Answer» `eV_s="hc"/lambda-phi_0` or `V_s="hc"/(elambda)-phi_0/e`
`V_s=(6.62xx10^(-34)xx3xx10^8)/(1.6xx10^(-19)xx2000xx10^(-10))-4.21`
or `V_s`=6.21-4.21= 2 V


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