InterviewSolution
Saved Bookmarks
| 1. |
Light of wavelength 2000 Å falls on a metallic surface whose work function is 4.21 eV. Calculate the stopping potential |
|
Answer» `eV_s="hc"/lambda-phi_0` or `V_s="hc"/(elambda)-phi_0/e` `V_s=(6.62xx10^(-34)xx3xx10^8)/(1.6xx10^(-19)xx2000xx10^(-10))-4.21` or `V_s`=6.21-4.21= 2 V |
|