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Light of wavelength 3500 A^(@) is incident on two metals A and B. Which metal will yield photoelectrons, if their work functions are 4.2 eV and 1.9 eV respectively ?

Answer»

Solution :`lambda=3500A^(@)=3500xx10^(-10)m, h=6.63xx10^(-34)JS`
`F=h upsilon=h(c )/(lambda)=(6.63xx10^(-34)xx3xx10^(8))/(3500xx10^(-10))J=(6.63xx10^(-34)xx3xx10^(8))/(3500xx10^(-10)xx1.6xx10^(-19))=3.546eV`


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