Light of wavelength `4000 Å` falls on a photosensitive metal and a negative `2 V` potential stops the emitted electrons. The work function of the material ( in eV) is approximately `( h = 6.6 xx 10^(-34) Js , e = 1.6 xx 10^(-19) C , c = 3 xx 10^(8) ms^(-1))`A. `1.1`B. `2.0`C. `2.2`D. `3.1`

Light of wavelength `4000 Å` falls on a photosensitive metal and a ne

1.	Light of wavelength `4000 Å` falls on a photosensitive metal and a negative `2 V` potential stops the emitted electrons. The work function of the material ( in eV) is approximately `( h = 6.6 xx 10^(-34) Js , e = 1.6 xx 10^(-19) C , c = 3 xx 10^(8) ms^(-1))`A. `1.1`B. `2.0`C. `2.2`D. `3.1`
Answer» Correct Answer - A Energy of incident light `E( eV) = (12375)/(4000) = 3.09 eV` Stopping potential is `- 2V` so `K_(max) = 2 eV` Hence by using `E = W_(0) + K_(max) rArr W_(0) = 1.09 ~~ 1.1` eV

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Light of wavelength `4000 Å` falls on a photosensitive metal and a negative `2 V` potential stops the emitted electrons. The work function of the material ( in eV) is approximately `( h = 6.6 xx 10^(-34) Js , e = 1.6 xx 10^(-19) C , c = 3 xx 10^(8) ms^(-1))`A. `1.1`B. `2.0`C. `2.2`D. `3.1`

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