1.

Light of wavelength 5000xx10^(-10)m is incident normally pattern is observed to lie atdistance of 5 mm from the central maximum onscreen place at a distance of 3 from the slit. Then the width of the slits is

Answer»

3 CM
`0.3 cm`
`0.03 cm`
`0.01 cm `

Solution :`asintheta=nlamda`
`:.AXX(X)/(D)=nlamda`
`:.a=(3xx5000xx10^(-10))/(5xx10^(-3))=0.3mm`


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